Hi

Using the standard slope-intercept form for an equation of a line y = mx + b

  where m is the slope and b the y-intercept.  

Line Perpendicular to 2x-3y=9  and passing thru Pt(3,-5)

 2x - 3y = 9  Or y = (-2/3)x -3  slope m = (-2/3)

New Line 

  y = (3/2)x + b

 -5 = (3/2)*-2 + b

 -2 = b

 y = (3/2)x - 2 (Blue Line)



 

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