SOLUTION: passes through the point (-1,6) and is perpendicular to the line whose equation is 4x+2y=3.

Question 432922: passes through the point (-1,6) and is perpendicular to the line whose equation is 4x+2y=3.
Found 2 solutions by Gogonati, robertb:
Answer by Gogonati(855) (Show Source): You can put this solution on YOUR website!
We know that two lines are perpendicular when the product of their slopes is -1.
First we write 4x+2y=3 in the slope-intercept form:, we see that
the slope of this line is m1=-2. Let's the slope of the perpendicular line, m2,
then m1*m2=-1, substitute m1=-2, (-2)*m2=-1 => m2=1/2.
Now we find the equation of line through the point (-1, 6) with slope m2=1/2:
, write it in the slope-intercept form.
, and in the standard form:

Done.
Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!
the equation of the perpendicular line must be 2x - 4y = c, where c is an unknown constant. To find c, use the coordinates of the given point:
2*-1 -4*6 = c, or -2 - 24 = c, or c = -26.
Hence the equation of the perpendicular line is 2x - 4y = -26, or x - 2y = -13.
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