SOLUTION: write the slope-intercept form of the line that passes through (0,-2) and is parallel to the line 5x+4y=3.

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Question 4316: write the slope-intercept form of the line that passes through (0,-2) and is parallel to the line 5x+4y=3.
Answer by rapaljer(4667) About Me  (Show Source):
You can put this solution on YOUR website!
The fact that this line passes through the point (0,-2) means that the y-intercept is -2, so in the formula y=mx+b, the value of b is -2.

Next, find the slope of the given line. To do this, you must solve for y.

5x+%2B+4y+=+3 Add -5x to each side of the equation.
5x+-+5x+%2B+4y+=+-5x+%2B+3
4y+=+-5x+%2B+3

Next divide both sides by 4 to express the given line in slope intercept form.
4y%2F4+=+-5x%2F4+%2B+3%2F4
y+=+-5x%2F4+%2B+3%2F4 so the slope m of the given line is -5%2F4
The slope of ANY line parallel to this line is also m+=+-5%2F4, so the final answer is
y+=+mx+%2B+b
y=-5x%2F4+-+2

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