SOLUTION: What is the equation of the line that passes through (4, -1) and (-2, 3)? Can you help me answer this? I keep getting y = -4/6x + ? and it has to be written in general form.

Question 417444: What is the equation of the line that passes through (4, -1) and (-2, 3)?
Can you help me answer this? I keep getting y = -4/6x + ? and it has to be written in general form.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
What is the equation of the line that passes through (4, -1) and (-2, 3)?
Can you help me answer this? I keep getting y = -4/6x + ? and it has to be written in general form.
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Find the slope, m
m = diffy/diffx = (3 - (-1))/(-2 -4) = 4/-6 = -2/3
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Use y = mx + b and either point to find b
-1 = (-2/3)*4 + b
b = -1 + 8/3 = 5/3
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Then it's y = mx + b
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The eqn is
y = (-2/3)x + 5/3
Or 2x + 3y = 5

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