SOLUTION: it say to use the substitutuon y=x+2 2x+y=8 x+y=3 3x+y=3 3x-y=9 2x+y=6 I hope you ca help I need to know how to do this for my exam

Question 41591: it say to use the substitutuon

y=x+2
2x+y=8

x+y=3
3x+y=3

3x-y=9
2x+y=6

I hope you ca help I need to know how to do this for my examine
Answer by Nate(3500) (Show Source): You can put this solution on YOUR website!
y=x+2
2x+y=8
Look at the first equation. (y = x + 2)-- has a solutions of
2x + y = 8
2x + x + 2 = 8
3x = 6
x = 2
So ....
y = x + 2
y = 2 + 2
y = 4
(2,4) is your solution! That is where the two line's meet.

------
x+y=3
3x+y=3
Change the first equation to by subtracting , so is equal to
3x + y = 3
3x + -x + 3 = 3
2x = 0
x = 0
So ....
x + y = 3
0 + y = 3
y = 3
(0,3) is your solution! That is where the two line's meet.

------
3x-y=9
2x+y=6
Change the second equation to by subtracting , so is equal to
3x - y = 9
3x - (-2x + 6) = 9
3x + 2x - 6 = 9
5x = 15
x = 3
So ....
2x + y = 6
2(3) + y = 6
6 + y = 6
y = 0
(3,0) is your solution! That is where the two line's meet.

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