SOLUTION: solve by any method of your choice: 2x^2-3x=20

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Question 411292: solve by any method of your choice:
2x^2-3x=20

Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!

Hi
2x^2-3x=20
2x^2-3x-20=0


x = (3 ± 13)/4
x = 4
x = -10/4 = -5/2
CHECKING our Answer***
(x-4)(x+5/2) = 0

2x^2 -3x-20 = 0
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