SOLUTION: Suppose the line through points (-1,6) and (x,2) is perpendicular to the graph of 2x + y = 3. Find the value of x
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Question 410222: Suppose the line through points (-1,6) and (x,2) is perpendicular to the graph of 2x + y = 3. Find the value of x
Found 2 solutions by nerdybill, solver91311:
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
Suppose the line through points (-1,6) and (x,2) is perpendicular to the graph of 2x + y = 3. Find the value of x
.
Find slope of
2x + y = 3
by rearranging into the "slope-intercept" form:
2x + y = 3
y = -2x + 3
slope then, is -2
.
A line perpendicular to this must have a slope that is the "negative reciprocal":
-2m = -1
m = 1/2
.
slope of (-1,6) and (x,2)
(y2-y1)/(x2-x1) = 1/2
(2-(-6))/(x-(-1)) = 1/2
(2+6)/(x+1) = 1/2
8/(x+1) = 1/2
cross-multiply:
16 = x+1
15 = x
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Step 1: Determine the slope of the line represented by the given equation.
Step 2: Determine the slope of any line perpendicular to the line represented by the given equation using the fact that perpendiculars have slopes that are negative reciprocals:
Step 3: Use the slope formula to determine an expression in 
for the slope of the line that passes through the two given points.
where )
and )
are the coordinates of the given points.
Step 4: Set the expression derived in Step 3 equal to the slope value determined in Step 2. Solve for .
John
My calculator said it, I believe it, that settles it
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