Hi

line that passes through (3, -2) and is perpendicular to y=3x-4 



y=3x-4    |slope m = 3  

perpendicular lines have slopes that are neagtive reciprocals of one another

New Line: m = -1/3   |Note: 3*-1/3 = -1

 y = (-1/3)x + b   |using ordered pair Pt(3,-2) to solve for b

-2 = -1 + b

 -1 = b 

 y = (-1/3)x - 1 |written in slope-intercept form



 

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