SOLUTION: In 1993 a farmer owned 250 acres. In 2004 he owned 312 acres. If this growth is linear, how many acres should he own in 2012. Write a linear equation to model his growth.

Question 406720: In 1993 a farmer owned 250 acres. In 2004 he owned 312 acres. If this growth is linear, how many acres should he own in 2012. Write a linear equation to model his growth.
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!



Hi

In 1993 a farmer owned 250 acres.  In 2004 he owned 312 acres.

Using the point-slope formula, 

(2004,312)and

(1993,250) m = 62/11

Using the standard slope-intercept form for an equation of a line y = mx + b

  where m is the slope and b the y-intercept:  

 y = (62/11)x + 250   |x is the years beyond 1993

how many acres should he own in 2012  x = 19

 y = (62/11)*19 + 250 

 y = 107 + 250 = 357 acres 

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