SOLUTION: find x. 2[9-(x-3)+4x]=4x-5(x+2)-8

Question 401659: find x.
2[9-(x-3)+4x]=4x-5(x+2)-8
Answer by algebrahouse.com(1659) (Show Source): You can put this solution on YOUR website!
2[9 - (x - 3) + 4x] = 4x - 5(x + 2) - 8
2[9 - x + 3 + 4x] = 4x - 5x - 10 - 8 {used distributive property}
2[3x + 12] = -x - 18 {combined like terms}
6x + 24 = -x - 18 {used distributive property}
7x + 24 = -18 {added x to both sides}
7x = -42 {subtracted 24 from both sides}
x = -6 {divided both sides by 7}

www.algebrahouse.com
RELATED QUESTIONS
9-2 x = -8-4x (answered by MathLover1)

8+3(x+2)=... (answered by josgarithmetic,addingup)

4x-8(x+2)=-4x-5 (answered by JBarnum)

x^3+4x^2-9 (answered by richwmiller)

X^2+4X=9 (answered by troymuga)

x^2 - 4x + 9 (answered by TimothyLamb)

Add: (4x^3-2x^2+x+4)+(9-x^5-x^2+4x) Thank... (answered by Fombitz)

Find f ' (x) if f(x)=(4x-5)^3 x... (answered by MathLover1,math_helper)

x+2=4x+8 (answered by fractalier)