SOLUTION: 1)6(z-2)= 3z-8+3z 2) 13 + 4w = -5(-w-6)+2(w+1)

Question 399518: 1)6(z-2)= 3z-8+3z
2) 13 + 4w = -5(-w-6)+2(w+1)
Answer by algebrahouse.com(1659) (Show Source): You can put this solution on YOUR website!
1)6(z-2)= 3z-8+3z
6z - 12 = 6z - 8 {used distributive property and combined like terms}
6z = 6z + 4 {added 12 to both sides}
0 = 4 {subtracted 6z from both sides}
= no solution

- When the variable disappears and you get a statement that is
never true, then there is no solution.

2) 13 + 4w = -5(-w-6)+2(w+1)
13 + 4w = 5w + 30 + 2w + 2 {used distributive property}
13 + 4w = 7w + 32 {combined like terms}
4w = 7w + 19 {subtracted 13 from both sides}
-3w = 19 {subtracted 7w from both sides}
w = -19/3 {divided both sides by -3}
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