SOLUTION: What is the range and domain of these problems in ordered pair form, or in inequality form pls...y=-3x-1 y=-3x^2+1 y=5 y=x^3-1 y=the square root of x y=(x+1)^(1/2)

Question 3980: What is the range and domain of these problems in ordered pair form, or in inequality form pls...y=-3x-1
y=-3x^2+1
y=5
y=x^3-1
y=the square root of x
y=(x+1)^(1/2)
y=(x-1)^(1/2)
y=(x^2+9)^(1/2)
y=(x-6)^(1/3)
y=6/(x-3)
Answer by longjonsilver(2297) (Show Source): You can put this solution on YOUR website!
1. y=-3x-1
domain is xeR
range is yeR

2. y=-3x^2+1
domain is xeR
range is yeR, y<=1

3. y=5
domain is xeR
range is y=5

4. y=x^3-1
domain is xeR
range is yeR

5. y=
domain is xeR, x>=0
range is yeR, y>=0

6. y=(x+1)^(1/2)
domain is xeR, x>=-1
range is yeR, y>=0

7. y=(x-1)^(1/2)
domain is xeR, x>=1
range is yeR, y>0

8. y=(x^2+9)^(1/2)
domain is xeR
range is yeR, y>=3

9. y=(x-6)^(1/3)
domain is xeR
range is yeR

10. y=6/(x-3)
domain is xeR, x not 3
range is yeR, y not 0

I have zipped through these - i may have overlooked something somewhere, but i think it is all correct.

The secret with domains and ranges is to know what a graph looks like, as tat tells you the answers.

jon.

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