SOLUTION: 3x^2*2x+7=0 then (x-1/3)^2 = can u please explain

Question 392886: 3x^2*2x+7=0 then (x-1/3)^2 =
can u please explain

Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
First, we need to complete the square

Start with the given expression.

Factor out the coefficient . This step is very important: the coefficient must be equal to 1.

Take half of the coefficient to get . In other words, .

Now square to get . In other words,

Now add and subtract inside the parenthesis. Make sure to place this after the "x" term. Notice how . So the expression is not changed.

Group the first three terms.

Factor to get .

Combine like terms.

Distribute.

Multiply.

So after completing the square, transforms to . So .

So is equivalent to .

Now let's isolate

Start with the given equation.

Subtract from both sides.

Multiply both sides by .

So the solution is

If you need more help, email me at jim_thompson5910@hotmail.com

Also, feel free to check out my tutoring website

Jim

RELATED QUESTIONS
If 3x^2-2x+7=0, Then... (answered by checkley71)

If 3x^2-2x+7=0 then... (answered by checkley71)

hi, If 3x^2-2x+7=0, then (x-1/3)^2=... (answered by jim_thompson5910)

If 3x^2-2x+7=0, then... (answered by stanbon)

If 3x^2-2x+7=0, then (x-1/3)^2 =... (answered by jim_thompson5910)

if 3x^2-2x+7=0 then (x-1/3)^2 (answered by ewatrrr)

This problem is an example in my book: 2(3x^2-2x+5) + (x^2+3x-7)distribute, remove... (answered by rfer)

By graphing,: 1. y-2x=0 x+y=3 2. 2x-y=1 x+2y=-2 3.2x-6=3y y+2=2/3x 4. 1/2x (answered by solver91311)

i need to no how to solve this problem can u show me... (answered by scott8148)