SOLUTION: Twice the first of three consecutive integers minus the third equals 58.Find the three integers

Algebra.Com
Question 391333: Twice the first of three consecutive integers minus the third equals 58.Find the three integers

Found 2 solutions by Alan3354, ewatrrr:
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
x = 1st
x+2 = 3rd
-------
2x - (x+2) = 58
x-2 = 58
x = 60

Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!

Hi,
Let x,(x+1),(x+2) represent the three consecutive integers
question states****
2x - (x+2) = 58
2x - x- 2) = 58
x = 60
the three consecutive integers are 60,61,62
CHECKING our Answer
120 - 62 = 58
RELATED QUESTIONS

Twice the first of three consecutive even integers minus the third equals 36. Find the... (answered by jojo14344)
Twice the first of three consecutive even integers minus the third equals 36. Find the... (answered by josmiceli)
twice the first of three consecutive even integers minus the third equals 36. Find the... (answered by stanbon)
PLEASE HELP ME PLEASE, twice the first of three consecutive integers minus the third... (answered by ewatrrr)
Twice the first of three consecutive even integers minus the third equals 36. Find the... (answered by ewatrrr)
Twice the first of three consecutive even integers minus the third equals 36. Find the 3... (answered by ankor@dixie-net.com)
Find three consecutive integers where the sum of the first two equals the square of the... (answered by Fombitz)
four times the second of three consecutive integers equals the sum of first and third... (answered by CubeyThePenguin)
Find three consecutive integers such that the sum of the first and twice the second is 98 (answered by JulietG)