Hi

the standard slope-intercept form for an equation of a line y = mx + b  

where m is the slope and b the y-intercept.  

finding in slope intercept form

(-6,-4) (-2,-2)



m = [-2-(-4)]  /[ -2-(-6)] = 2/4 = 1/2

Slope m = 1/2

 y = (1/2)x + b  using ordered pair Pt(-2,-2) to solve for b

 -2 = (1/2)*-2 + b

 -2 = -1 + b

 -1 = b

y = (1/2)x - 1



 

Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!
 

here is your answer:







 
Solved by pluggable solver: FIND EQUATION of straight line given 2 points
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (-6, -4) and (x2, y2) = (-2, -2).

  Slope a is .

  Intercept is found from equation , or . From that, 

  intercept b is , or .

  

  y=(0.5)x + (-1)

  

  Your graph:

  

  

  

 

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