SOLUTION: the slope-intercept equation for the line that passes through (-8, -11) and is perpendicular to -2x � 7y = -14

Question 387400: the slope-intercept equation for the line that passes through (-8, -11) and is perpendicular to -2x � 7y = -14
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
the slope-intercept equation for the line that passes through (-8, -11) and is perpendicular to -2x � 7y = -14
.
Determine slope of:
-2x � 7y = -14
�7y = 2x-14
y = (-2/7)x + 2
slope is -2/7
.
A line perpendicular to above must have a slope that is a "negative reciprocal":
(-2/7)m = -1
m = 7/2
.
plug given point and slope into "point-slope" form:
y - y1 = m(x - x1)
y - (-11) = (7/2)(x - (-8))
y + 11 = (7/2)(x + 8)
y + 11 = (7/2)x + 28
y = (7/2)x + 17 (this is what they're looking for)

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