Hi

Line perpendicular to 4x-2y+2=0  OR y = 2x+1  slope = 2

New line will have a slope = -1/2  (negative reciprocal of 2)

the standard 'slope-intercept form' for an equation of a line: y = mx + b 

 where m is the slope and b the y-intercept.  

y = -.5x + b Using ordered pair Pt(1,4) to solve for b

 4 = -.5*1 + b

 4.5 = b

y = -.5x + 4.5  OR   5x + 10y = 45 (in standard from)



 

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