Hi,

Line perpendicular to the graph of 

3x – 5y = 20  Solving for y to put into the slope-intercept form

3x - 20 = 5y

(2/5)x - 4 = y

Note: the standard slope-intercept form for an equation of a line is y = mx + b  

where m is the slope and b the y-intercept.  

y = (2/5)x - 4 slope of this line is (2/5), line perpendicular to it m = -(5/2}

New line:

 y  = (-5/2)x + b  using ordered pair Pt(-1,0) to solve for b

 0  = -5/2(-1) + b

 -5/2 = b

y = (-5/2)x - 5/2



 

RELATED QUESTIONS

Write the slope-intercept form of an equation for a line that passes through (-1,0) and... (answered by vleith)

Wite the slope-intercept form of an equation for a line that passes through (-1,0) and is  (answered by nerdybill,uday1435)

Write an equation in slope-intercept form of the line that is perpendicular to the graph... (answered by checkley71)

write the slope -int form for an equation of a line that passes through (0,4) and is... (answered by jim_thompson5910)

I need to write an equation in slope intercept form for the line that passes through the... (answered by ewatrrr)

write an equation in slope intercept form of the line that passes through (-7,2) and is... (answered by josgarithmetic,greenestamps)

write an equation in slope-intercept form for the line that satisfies each set of... (answered by rainy)

write an equation in slope-intercept form for the line that passes through (-4,3) and is... (answered by solver91311)

in slope intercept form write an equation for a line that is perpendicular to the line... (answered by solver91311)