AND, last but not least...
write the equation point that has the solution point's (3,2) and (1,0)
PLEASE EXPLAIN HOW TO GET THE ANSWERS THANKS A BUNCH.
~EVY~
Answer by sonimyke(4)   (Show Source): You can put this solution on YOUR website!
Equation for a solution line that has the solution points of (4,10) and (-2,4).
First, find the slope of the line using the formula (y1-y2)/(x1-x2)
y1=10, y2=4, x1=4, x2=-2.
slope=10-4/4--2
slope=6/6
slope=1
Secondly, find the y-intercept by substituting values for the variables in the equation y=mx+b. I will use the point (4,10).
10=1(4)+b
10=4+b
10-4=b
6=b
b=6 so the y-intercept is 6.
there fore, the equation of the line is going to be y=x+6.

what unique ordered pair will satisfy both of the following equations:
5x+2y=1-equation 1
2x+3y=7-equation 2
multiply equation 1 through by 3 and equation 2 through by 2.
the new equations are going to be
15x+6y=3-equation 1
4x+6y=14-equation 2
subtract equation 2 from equation 1
15x+6y= 3
- 4x+6y=14
you should then getthe equation
11x=-11
11x/11=-11/11 (divide both sides by 11)
x=-1
to find y, substitute -1 in any one of the equations for x.
5(-1)+2y=1
-5+2y=1
2y=1+5
2y=6 (divide both sides by 2)
y=3
therefore, the unique ordered pair is (-1,3)
write the equation point that has the solution point's (3,2) and (1,0)
Like the first question I solved, you first find the slope.
2-0/3-1=2/2
slope=1
I would like to use the point (3,2) to find the y-intercept.
y=mx+b
2=1(3)+b
2=3+b
2-3=b
-1=b
Since b=-1, the y-intercept is -1.
therefore, the equation is going to be y=x-1