SOLUTION: PLEASE HELP. I tried this problem but am stumped. Find an equation of the line containing the given pair of points. (1/4, - 1/2) and (3/4, 6). What is the equation of the

Algebra ->  Linear-equations -> SOLUTION: PLEASE HELP. I tried this problem but am stumped. Find an equation of the line containing the given pair of points. (1/4, - 1/2) and (3/4, 6). What is the equation of the      Log On


   

Question 375822: PLEASE HELP.
I tried this problem but am stumped.
Find an equation of the line containing the given pair of points.
(1/4, - 1/2) and (3/4, 6). What is the equation of the line?
This is what I have so far;

-1/3 - 5
____________ ??
1/6 - 5/6
Thank you
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi,

Finding an equation of the line containing the given pair of points. 

The standard slope-intercept form for an equation of a line y = mx + b  

where m is the slope and b the y-intercept.  

(1/4, - 1/2) and (3/4, 6) Using the points to find the slope m 

m+=%28y%5B2%5D+-+y%5B1%5D%29%2F%28x%5B2%5D+-+x%5B1%5D%29

m+=+%286-%28-1%2F2%29%29%2F%28%283%2F4%29+-+%281%2F4%29%29

m = (13/2)/(1/2) = 13

y = 13x + b  using Pt(3/4,6) to solve for b

6 = 39/4 + b

-15/4 = b

y = 13x - 15/4