SOLUTION: Another problem just like the last one I couldn't figure out 16x^-7y^-2/4x^5y^2

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Question 37553This question is from textbook
: Another problem just like the last one I couldn't figure out
16x^-7y^-2/4x^5y^2This question is from textbook

Answer by fractalier(2101) About Me  (Show Source):
You can put this solution on YOUR website!
Remember that negative exponents on the top are positive exponents on the bottom...so starting from
16(x^-7)(y^-2) / 4(x^5)(y^2)
we will move the negative exponents to the bottom and combine, yielding
4 / (x^12)(y^4)
notice we reduced the coefficients too...