SOLUTION: find an equation that satisfies the points (9,136) and (3,40)

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Question 375059: find an equation that satisfies the points (9,136) and (3,40)
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

First let's find the slope of the line through the points and


Note: is the first point . So this means that x%5B1%5D=9 and y%5B1%5D=136.
Also, is the second point . So this means that x%5B2%5D=3 and y%5B2%5D=40.


m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29 Start with the slope formula.


m=%2840-136%29%2F%283-9%29 Plug in y%5B2%5D=40, y%5B1%5D=136, x%5B2%5D=3, and x%5B1%5D=9


m=%28-96%29%2F%283-9%29 Subtract 136 from 40 to get -96


m=%28-96%29%2F%28-6%29 Subtract 9 from 3 to get -6


m=16 Reduce


So the slope of the line that goes through the points and is m=16


Now let's use the point slope formula:


y-y%5B1%5D=m%28x-x%5B1%5D%29 Start with the point slope formula


y-136=16%28x-9%29 Plug in m=16, x%5B1%5D=9, and y%5B1%5D=136


y-136=16x%2B16%28-9%29 Distribute


y-136=16x-144 Multiply


y=16x-144%2B136 Add 136 to both sides.


y=16x-8 Combine like terms.


y=16x-8 Simplify


So the equation that goes through the points and is y=16x-8


If you need more help, email me at jim_thompson5910@hotmail.com

Also, feel free to check out my tutoring website

Jim