SOLUTION: it's me again... not sure as to what i did wrong on this one.
the directions are to give the coordinates of the point where each line crosses the y-axis. y = -3x
my answer: (
Algebra.Com
Question 37189: it's me again... not sure as to what i did wrong on this one.
the directions are to give the coordinates of the point where each line crosses the y-axis. y = -3x
my answer: (-3,0) (o,1) do you mind helping with this one? thanx!! :)
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
When a line crosses the y-axis, its x-value is zero. Merely plug x = 0 into y = -3x and find that y = 0 too. So it goes thru (0, 0).
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