SOLUTION: solve the given system by substitution:
5x-3y=7
x-6y=-4
Algebra.Com
Question 35785: solve the given system by substitution:
5x-3y=7
x-6y=-4
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
5x-3y=7
x-6y=-4 or x=6y-4 substituting 6y-4 for x in the first equation we get
5(6y-4)-3y=7 or 30y-20-3y=7 27y=27 or y=27/27 or y=1 thus
x-6*1=-4 or x-6=-4 or x=2
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