SOLUTION: how do you do contains point (0,4) and is parallel to y=2x-3? (characteristics of linear functions)

Question 353341: how do you do contains point (0,4) and is parallel to y=2x-3? (characteristics of linear functions)
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
how do you do contains point (0,4) and is parallel to y=2x-3? (characteristics of linear functions)
.
Since your new line is parallel to
y=2x-3
it MUST have the same slope.
The slope of
y=2x-3
is 2
this is from inspection because the equation is already in "slope-intercept" form:
y = mx + b
.
Given slope is 2 and one point (0,4)
plug into "point-slope" form:
y - y1 = m(x - x1)
y - 4 = 2(x - 0)
y - 4 = 2x
y = 2x + 4 (this is what they're looking for)

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