SOLUTION: write an equation of the line containg the given point and parallel to the given line..
(6,-1); 4x-(-5y)=6
4x minus negative 5y = 6
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Question 349438: write an equation of the line containg the given point and parallel to the given line..
(6,-1); 4x-(-5y)=6
4x minus negative 5y = 6
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
(6,-1); 4x-(-5y)=6
4x-(-5y)=6
4x+5y=6
5y=-4x+6
y=-4x/5 +6/5
slope = -4/5
...
slope of line parallel to this line will also be -4/5
..
it passes through (6,-1)
plug values of x,y,m to find b in equation y = mx+b
-1=-4/5 * 6 +b
-1=-24/5 +b
-1+24/5=b
(-5+24)/5 =b
b=19/5
The equation is
y = -4x/5 + 19/5
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