SOLUTION: What is the equation of a line perpendicular to the line 7x + 4y = 15 + 2x and passing through the point (0.5, 0.5)?

Algebra ->  Linear-equations -> SOLUTION: What is the equation of a line perpendicular to the line 7x + 4y = 15 + 2x and passing through the point (0.5, 0.5)?      Log On


   

Question 348166: What is the equation of a line perpendicular to the line 7x + 4y = 15 + 2x and passing through the point (0.5, 0.5)?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
Hi
*Note solve 7x + 4y = 15 + 2x for y in order to determine the slope of this line.
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y+=+%28-5%2F4%29x+%2B+%2815%2F4%29
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y = mx + b
Slope of this line is (-5/4)
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The slope of a line perpendicular to this line would be the negative reciprocal or (4/5)
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Sutitute slope and point ( .5, .5 )into the slope point form for a line
y++=+m%28x+-+x%5B1%5D%29%2By%5B1%5D
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y=+%284%2F5%29%2A%28x-%281%2F2%29%29+%2B+%281%2F2%29
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Simplify:
y=+%284%2F5%29%2Ax-%284%2F10%29+%2B+%285%2F10%29
y=+%284%2F5%29%2Ax%2B%281%2F10%29
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check your answer with point given (.5,.5)