SOLUTION: Find the equation for the line passing through the point (-1,-4) and perpendicular to the line whose equation is 1 x + 3y + 1=0.

Question 346714: Find the equation for the line passing through the point (-1,-4) and perpendicular to the line whose equation is 1 x + 3y + 1=0.
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
1 x + 3y + 1=0
3y=-x-1
y=-x/3-1/3 (red line). Slope=-1/3
(-1,-4) and perpendicular.
The perpendicular line will have a slope=3
Y=mX+b
-4=3*-1+b
-4=-3+b
b=-4+3
b=-1 the Y intercept.
Y=3X-1 answer. (green line)
(graph 300x300 pixels, x from -6 to 5, y from -6 to 5, of TWO functions -x/3 -1/3 and 3x -1).
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