SOLUTION: Write the equation of the line that is perpendicular to the line 3x - 2y = 6 and passes through the point (-1,2).

Question 332855: Write the equation of the line that is perpendicular to the line 3x - 2y = 6 and passes through the point (-1,2).

Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
3x - 2y = 6 and passes through the point (-1,2).
-2y=-3x+6
y=-3x/-2+6/-2
y=3x/2-3 (red line)
This line has a slope=3/2
Thus a perpendicular line will have a slope=-2/3.
2=-2/3*-1+b
2=2/3+b
b=2-2/3
b=(2*3-2)/3
b=(6-2)/3
b=4/3 is the Y intercept.
Y=-2X/3+4/3. (green line)
(graph 200x200 ixels, x from -5 to 5, y from -5 to 5, of TWO functions 3x/2 -3 and -2x/3 +4/3).
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