View quadratic equation below
x=1,-0.5
to find y simply plug in the x's
y=1,0

You don't need to use the quadratic formula,
as the other tutor used, because it leads to 
a factorable quadratic:



Solve the second equation for y:

 

Substitute  in the first equation in the system



So there are two solutions for x.  We
must find a value of y for each of them,
by substituting each in 

Substituting ,





So one solution is (x,y) = (,-2) 

Substituting ,





So the other solution is (x,y) = (1,1)

---------------------------

Checking (x,y) = (,-2)







 

Checking (x,y) = (1,1)









Edwin