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Question 3287: Hi again, Drglass. Thanks for responding so soon. Your examples are real clear and precise. I tried it and so the next numbers would have to be 52 and 79 using x for 7 and 11.
Theres also this nth term: an=26n-2-n for T and an=3n-2+n+1 for x
if you plugged in 3,7, and 11, it would come up the same. And together: 15n+1+3x+6n-6=T. Does this also make sense? I'm not so sure if it does. I'd appreciate your input. -Maria
Answer by drglass(89)   (Show Source):
You can put this solution on YOUR website! I'm not certain about this. If you are asking for the nth number in the sequence 25, 52, 79 ..., consider the difference between to consecutive numbers in the sequence. The difference between 79 and 52 is 27, likewise, the difference between 79 and 52 is 27. This suggests that the equation will have the form 27n + c, where c is some constant. Now consider the first value 25. The equation tells us that  , so the c must equal -2. Therefore, the nth number in the sequence is  . This is close to what you've got,  , if you had  , then our analyses would agree.
For x, I would follow the same technique. The sequence we have is 3, 7, 11,... which means the difference between consecutive numbers is 4. This means the nth number is  . To find this constant, look at the first value.  means the constant must be -1, so our equation is 4n - 1. Interestingly, this is the same as your solution after a little algebra.
I'm not sure why you want to combine them.
Does this make sense?
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