SOLUTION: find the points of intersection of the circle x^2+y^2-x-3y-0 and the line y=x-1
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Question 325733: find the points of intersection of the circle x^2+y^2-x-3y-0 and the line y=x-1
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Start with your circle equation:
Then substitute the expression in 
that is equal to 
for in the circle equation:
^2\ -\ x\ -\ 3\left(x\ -\ 1\right)\ =\ 0)
Simplify, collect like terms, and factor the resulting quadratic. The roots will be the -coordinates of the two points of intersection. The -coordinates can be easily determined by substitution in 
John
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