SOLUTION: The perimeter of a rectangle is 242 inches. The length exceeds the width by 55 inches. Find the length and width.
Algebra.Com
Question 321849: The perimeter of a rectangle is 242 inches. The length exceeds the width by 55 inches. Find the length and width.
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
let width be x
length = x+55
Perimeter = 2L+2W
2*x+2(x+55)=242
2x+2x+110=242
4x=132
x=132/4
x=33 , which is the width
Length = x+55
= 33+55=88 inches
RELATED QUESTIONS
the perimeter of a rectangle is 242 inches. the length exceeds the witdth by 43 inches... (answered by rfer)
perimeter of a rectangle is 112 inches the length exceeds the width by 4 inches find the... (answered by rfer)
What are the length and width of a rectangle of the length exceeds the width by 55 inches (answered by stanbon)
The perimeter of a rectangle is 230 inches. The length exceeds the width by 47 inches.... (answered by rdamanik)
The perimeter of a rectangle is 94 inches. The length exceeds the width by 5 inches.... (answered by Jstrasner)
The perimeter of a rectangle is 104 inches. The length exceeds the width by 14 inches.
(answered by tm.hodgson)
The perimeter of a rectangle is 108 inches. The length exceeds the width by 8 inches.... (answered by oscargut)
the perimeter of a rectangle is 196 inches. The length exceeds the width by 22 inches.... (answered by meshe43)
the perimeter of a rectangle is 70 inches the length exceeds the width by 19 inches. Find (answered by checkley77)