SOLUTION: Find the equation of the line passing through (-1, 2) and perpendicular to y = 3x + 5.

Question 319556: Find the equation of the line passing through (-1, 2) and perpendicular to y = 3x + 5.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
A line and a point example.
Write in standard form the eqation of a line that satisfies the given conditions. Perpendicular to 9x+3y=36, through (1,2)
-----------------
Find the slope of the line. Do that by putting the equation in slope-intercept form, y = mx + b. That means solve for y.
9x+3y = 36
3y= - 9x + 36
y = -3x + 12
The slope, m = -3
------------------
The slope of lines parallel is the same.
The slope of lines perpendicular is the negative inverse, m = +1/3
----------------
Use y = mx + b and the point (1,2) to find b.
2 = (1/3)*1 + b
b = 5/3
The equation is y = (1/3)x + 5/3 (slope-intercept form)
x - 3y = -5 (standard form)
------------------------
For further assistance, or to check your work, email me via the thank you note, or at Moral Loophole@aol.com
RELATED QUESTIONS
Find the equation of the line passing through (-1, 2) and perpendicular to y = 3x + 5. (answered by jim_thompson5910)

6. Find the equation of the line passing through (-1, 2) and perpendicular to y = 3x (answered by MathLover1)

find the equation a line perpendicular to y=3x-2 and passing through... (answered by Alan3354)

passing through (-9,2) and perpendicular to the line whose equation is... (answered by Maths68)

Find the equation of the line passing through ( -2, -1) and parallel to y =-3X... (answered by Alan3354)

Find the equation of the line passing through (1/2, 3/4) and is perpendicular to... (answered by AnlytcPhil)

Find the equation in standard form, of the line perpendicular to 3x - 6y = 9 and passing... (answered by sdmmadam@yahoo.com)

Find the equation of the line passing through (-1, -3) and perpendicular to y = -2x +... (answered by mananth)

Find equation, in standard form, of the line perpendicular to 3x - 6y =9 and passing... (answered by Cintchr)