SOLUTION: Please help me graph 3y>12x+15
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Question 319373: Please help me graph 3y>12x+15
Found 2 solutions by solver91311, stanbon:
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Step 1: Change the relationship symbol to "=". Graph the resulting line. If the original relationship symbol was 
or 
, do it with a dashed or broken line. If your symbol was 
or 
, graph the equation with a solid line.
Step 2: Pick any point on the coordinate plane that does not lie on the line you just graphed. If the line does not pass through the origin, )
, then the origin is an excellent choice for this step. If the line does pass through the origin, select a point other than the origin -- I recommend a point that has small integer coordinates.
Step 3: Substitute the values of the coordinates of the point chosen in Step 2 for the corresponding variables in the inequality you started with in Step 1.
Step 4: Do the appropriate arithmetic to determine whether the substitution created a true statement or not. If you created a true statement, shade in the side of the line containing the point selected in Step 2. If you created a false statement, shade in the side of the line that does not contain the selected point.
John
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Please help me graph 3y>12x+15
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Graph the boundary y = 4x + 5 as a dashed line.
---
-------------
Select a test point like (0,0)
-------
Test it in the inequality:
3*0 > 12*0 + 15
0 > 15
That is false and means the solution set of the inequality
is not on the (0,0) side of the boundary.
The solution set is on the other side.
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===========
Cheers,
Stan H.
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