Question 315131: solve this linear equation by elimination and substitution and work must be shown.
2x-4y=-4 and 4x+5y=48.
Thanks Answer by malaydassharma(59) (Show Source): You can put this solution on YOUR website! Elimination Method:
2x-4y=-4 ..(i)
4x+5y=48 ..(ii)
Multiplying (i) by 2
4x-8y=-8 ..(i)
4x+5y=48 ..(ii)
subtracting (i) - (ii) we get
-13y=-56
y=56 / 13
2x-4y=-4 ..(i)
4x+5y=48 ..(ii)
Multiplying (i) by 5 and (ii) by 4
10x-20y=-20 ..(i)
16x+20y=192 ..(ii)
Adding (i) + (ii) we get
26x=172
x=172/26= 86/13
*****************************************************
Substitution Method:
Solve: We'll use substitution. After moving -4*y to the right, we get: , or . Substitute that
into another equation: and simplify: So, we know that y=4.30769230769231. Since , x=6.61538461538462.