# SOLUTION: the perimeter of a rectangle is 100ft and the area is 400ft(squared).find the dimensions of the rectangle. could u write out the full answer step by step

Algebra ->  Algebra  -> Linear-equations -> SOLUTION: the perimeter of a rectangle is 100ft and the area is 400ft(squared).find the dimensions of the rectangle. could u write out the full answer step by step      Log On

 Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations! Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!

 Algebra: Linear Equations, Graphs, Slope Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Linear-equations Question 310373: the perimeter of a rectangle is 100ft and the area is 400ft(squared).find the dimensions of the rectangle. could u write out the full answer step by stepAnswer by ankor@dixie-net.com(15747)   (Show Source): You can put this solution on YOUR website!Write an equation for each statement: : "the perimeter of a rectangle is 100ft" 2L + 2W = 100 Simplify, divide thru by 2, results L + W = 50 To use for substitution later, write it: L = (50-W) : "the area is 400ft(squared)" L * W = 400 From the perimeter; replace L with (50-W) in the above equation (50-W) * W = 400 50W - W^2 = 400 Arrange as a quadratic equation -W^2 + 50W - 400 = 0 Easier to factor if we change the signs, multiply by -1, results: W^2 - 50W + 400 = 0 Factors to (W-40)(W-10) = 0 Two solutions W = 40 and W = 10 : .find the dimensions of the rectangle. If W = 40, remember L = (50-W), then L = 50 - 40 L = 10 : If W = 10, then L = 50 - 10 L = 40 : Generally the length is the longer dimension so 40 by 10 would be the answer : : You can check this solution by finding the perimeter with these values : Was this step-by-step enough to give you an understanding of this??