SOLUTION: Write the equation of a line that is perpendicular to the given line and that passes through the given point:
y=2/3x+9;(-6,5)
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Question 306870: Write the equation of a line that is perpendicular to the given line and that passes through the given point:
y=2/3x+9;(-6,5)
Found 2 solutions by Fombitz, texttutoring:
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Perpendicular lines have slopes that are negative reciprocals.
Use the point (-6,5) to solve for b.
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Answer by texttutoring(324) (Show Source): You can put this solution on YOUR website!
Perpendicular lines have slopes that are negative reciprocals of each other.
The original line has a slope of m=2/3, so a line perpendicular to it will have a slope of m=-3/2
You know that the second line passes through (-6,5), so this tells us that x=-6, and y=5. Use y=mx+b, the equation of a line, to solve for b:
y=mx+b
5=(-3/2)(-6) + b
5 = 18/2 + b
5 = 9 + b
b = -4
The equation of the perpendicular line is y=(-3/2)x -4
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