SOLUTION: Write the equation of the line that is perpendicular to the line: y=2x-3 and passes through the point (-2,2).

Question 303248: Write the equation of the line that is perpendicular to the line: y=2x-3 and passes through the point (-2,2).
Answer by texttutoring(324) (Show Source): You can put this solution on YOUR website!
That line has a slope of 2. A line perpendicular to it will have a slope that is the negative reciprocal of 2:

m = -1/2

Now use this slope in the equation of a line, y=mx+b. We know x and y because it tells us the line passes through the point (-2,2)

y=mx+b
2=(-1/2)(-2) + b
2=(-2/-2) + b
2=1+b
1=b

So m = -1/2 and b=1. The equation of the line that is perpendicular to y=2x-3 is:

y=(-1/2)x + 1
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