SOLUTION: solve by substitution
I need help finding the response to these sentences
2m+n=16
m-3n=15
Algebra.Com
Question 289137: solve by substitution
I need help finding the response to these sentences
2m+n=16
m-3n=15
Found 2 solutions by jim_thompson5910, stanbon:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Start with the first equation.
Subtract 2m from both sides.
Move on to the second equation.
Plug in
Distribute.
Combine like terms on the left side.
Add 48 to both sides.
Combine like terms on the right side.
Divide both sides by 7 to isolate m.
Reduce.
Go back to the previously isolated equation.
Plug in
Multiply -2 and 9 to get -18
Add -18 to 16 to get -2
So the solutions are and
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
2m+n=16
m-3n=15
-----
Comment: It's up to you to decide which variable
you are going to eliminate.
If you want to eliminate the "n" terms,
Multiply thru the 1st equation by 3, then add the two equations:
6m + 3n = 48
m - 3n = 15
--------------
7m = 63
m = 9
----
Substitute into either of the original equations and solve for "n":
9-3n = 15
-3n = 6
n = -2
-------------------
Cheers,
Stan H.
=====================
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