SOLUTION: Write an equation of the line containing the given point and perpendicular to the given line. (8,-6); 3x+5y=8. The equation of the line is y=

Question 285679: Write an equation of the line containing the given point and perpendicular to the given line. (8,-6); 3x+5y=8. The equation of the line is y=
Found 2 solutions by richwmiller, nyc_function:
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
Just curious.
Had you looked for similar problems before posting?
Had you looked for lessons before posting?

Answer by nyc_function(2741) (Show Source): You can put this solution on YOUR website!
The line we are looking for is perpendicular to the given equation, which means that its slope is the negative reciprocal of the slope of the given equation.
3x + 5y = 8
5y = -3x + 8
y = (-3/5)(x) + 8
The negative reciprocal of (-3/5) is (5/3) because (-3/5) times (5/3) = -1.
We now plug (5/3) and your point (8, -6) into the point-slope formula and solve for y.
y - (-6) = (5/3)(x - 8)
y + 6 = (5/3)(x) - 40/3
y = (5/3)(x) - 40/3 - 6
y = (5/3)(x) - 22/3

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