SOLUTION: The line passing through (-2,y) and (1,0) is perpendicular to line joining (3,3) and (-1,1). Find y. Thank you.

Question 281765: The line passing through (-2,y) and (1,0) is perpendicular to line joining (3,3) and (-1,1). Find y.
Thank you.
Found 2 solutions by subudear, richwmiller:
Answer by subudear(62) (Show Source): You can put this solution on YOUR website!
Let the slope of first line be m1 and slope of second line be m2 then
for both lines to be perpendicular to each other m1*m2 = -1
lets find m1 and m2
m1 = (0 - y) / [1 - (-2)] = -(y)/3
m2 = (1 - 3) / (-1 - 3) = 2/4 = 1/2
m1*m2 = -1
-(y)/3 * 1/2 = -1
-(y)/6 = -1
y = 6
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
find the slope of the line with points (3,3) and (-1,1)
y-y/x-x=m
1-3/-1-3=-2/-4=1/2
the slope of the line perpendicular is -2
y-y/x-x=m
0-y/1-(-2)=-2
-y/3=-2
y=6

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