SOLUTION: How would you graph linear equation 3x+5y=15

Question 280831: How would you graph linear equation 3x+5y=15
Answer by oberobic(2304) (Show Source): You can put this solution on YOUR website!
First, get the equation into slope-intercept form: y = mx+b
.
3x + 5y = 15
5y = -3x + 15
y = -3/5x+ 3
.
The y-intercept is where x=0, which equals 3. The point is (0, 3).
.
The x-intercept is where y = 0.
0 = -3/5x + 3
x = 5
The point is: (5,0)
.
With two points, you can draw a line.
.

.
Done
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