SOLUTION: graph the equation using the slope and the y intercept y=8/3x + 3

Question 280629: graph the equation using the slope and the y intercept
y=8/3x + 3
Answer by oberobic(2304) (Show Source): You can put this solution on YOUR website!
The presented problem is in slope-intercept form: y = mx + b.
m = slope
b = y-intercept.
.
y = 8/3x +3
.
slope = 8/3
y-intercept = 3
.
which defines the point (0,3)
.
We know the slope = rise / run = change in y / change in x.
.
So for every change of 3 in x, we have a change of 8 in y.
.
That allows us to define another point: (0+3, 8+8) or (3,16)
.
You can graph the line using the two points, so pick the x-intercept as another.
The x-intercept is where y=0.
0 = 8/3x +3
-8/3x = 3
-8x = 9
x = -9/8
thus defining the point (-9/8,0)
.

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