SOLUTION: graphing linear inequalities y=1/3x+5

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Question 280274: graphing linear inequalities y=1/3x+5
Answer by jim_thompson5910(33401) About Me  (Show Source):
You can put this solution on YOUR website!

Looking at y=%281%2F3%29x%2B5 we can see that the equation is in slope-intercept form y=mx%2Bb where the slope is m=1%2F3 and the y-intercept is b=5

Since b=5 this tells us that the y-intercept is .Remember the y-intercept is the point where the graph intersects with the y-axis

So we have one point

Now since the slope is comprised of the "rise" over the "run" this means

Also, because the slope is 1%2F3, this means:


which shows us that the rise is 1 and the run is 3. This means that to go from point to point, we can go up 1 and over 3

So starting at , go up 1 unit

and to the right 3 units to get to the next point

Now draw a line through these points to graph y=%281%2F3%29x%2B5

So this is the graph of y=%281%2F3%29x%2B5 through the points and