SOLUTION: Please show me how to graph 15x-5y=45 using the x- and y-intercepts. What is the slope and the y intercept in the problem?
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Question 271328: Please show me how to graph 15x-5y=45 using the x- and y-intercepts. What is the slope and the y intercept in the problem?
Found 4 solutions by stanbon, solver91311, LarissaRichardson, Zyzden:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Please show me how to graph 15x-5y=45 using the x- and y-intercepts. What is the slope and the y intercept in the problem?
---------------------------
15x-5y=45
x-intercept:
Let y = 0, then 15x = 45 and x = 3
giving you point(3,0)
---------------------
y-intercept:
Let x = 0, then -5y=45 and y = -9
giving you point (0,-9)
----
Plot those two points and draw a line thru them:
==============================
cheers,
Stan H.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Substitute 0 for 
and then solve what is left for 
, giving you some value for such as 
. (Determining the value of 
is left as an exercise for the student). That gives you the coordinates of one ordered pair, )
, which happens to lie somewhere on the -axis -- hence the name -intercept.
Now repeat the same process substituting 0 for and creating a second ordered pair, interestingly enough called the -intercept, of the form )
. Again, the value of 
is up to you.
Plot both points. Draw a line extending all the way across your graph through the two points.
John
Answer by LarissaRichardson(34) (Show Source): You can put this solution on YOUR website!
15x-5y=45
Rewrite
5y=15x-45
Divide by 5
y=15x/5-45/5
y=3x-9
y=mx+b
m=3
b=-9
The slope is 3
The y intercept is -9
Answer by Zyzden(7) (Show Source): You can put this solution on YOUR website!
1.) First to make our lives easier, let us right this equation in standard form; ie: y=function of x --> in our case lets first subtract 15x from both sides
-->
Next let's divide both sides by -5
-->
Now we are in standard form.
2.) To find the y-intercepts (where the graph crosses the y-axis) we simply plug 0 in for x and solve for y.
--> --> ; this tells us our graph crosses the y-axis at -9.
3.) To find the x-intercepts (where the graph crosses the x-axis) we simply plug 0 in for y and solve for x.
--> --> --> ; this tells us our graph crosses the x-axis at 3.
If you plot these two points [(0,-9) & (3,0)] and draw a line between them, you have the graph of your equation
GRAPH:
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