SOLUTION: ***CAN SOMEONE PLS HELP ME! this is really about factoring in groups. this symbol ^# indicate exponents.. thank you so much!!
3x^2 + 17x + 10
5y^8 - 125
a^2- 2ab - 1
Algebra.Com
Question 27126: ***CAN SOMEONE PLS HELP ME! this is really about factoring in groups. this symbol ^# indicate exponents.. thank you so much!!
3x^2 + 17x + 10
5y^8 - 125
a^2- 2ab - 15b^2
4c^2 - 12c + 9
p^4 - 1
6y^2 - 54
x^2 + 10x + 21
a^2 - 10ab + 3b^2
5x^2 - 10^x
x^2+ 12xy + 35y^2
Answer by elima(1433) (Show Source): You can put this solution on YOUR website!
3x^2 + 17x + 10
You know both signs in the parenthesis are going to +, because the second sign is a +;
(3x+_)(x+_)
Now what are the factors of 10: 1,10; 2,5;
We will use 2,5;
(3x+2)(x+5)
5y^8 - 125
First you look to see if you can factor out anything? yes; 5
5(-25)
You know the signs in the parethesis are - & +, because of the -25;
5()
a^2- 2ab - 15b^2
The signs in the parethesis are what? - & +
(a+_)(a-_)
What are the factors of 15, but when subtracted = 2? 3,5
(a+3)(a-2)
4c^2 - 12c + 9
(2c-_)(2c-_)
(2c-3)(2c-3)
p^4 - 1
(
6y^2 - 54
6
6(y-3)(y+3)
x^2 + 10x + 21
(x+7)(x+3)
a^2 - 10ab + 3b^2
(a+3b)(a-5b)
5x^2 - 10^x
5x(x-2)
x^2+ 12xy + 35y^2
(x+7)(x+5)
=)
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