SOLUTION: identify the slope and y intercept of the graph of the equation. then graph. y= -5/4x+1 I am not sure how to graph this and is the answer -4/5;y-intercept:-1 or am I wrong

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Question 269403: identify the slope and y intercept of the graph of the equation. then graph.
y= -5/4x+1
I am not sure how to graph this and is the answer -4/5;y-intercept:-1 or am I wrong

Answer by JBarnum(2146)   (Show Source): You can put this solution on YOUR website!
use the equation y=mx+b where m=slope and b=y-intercept

slope = y-axis/x-axis

im not going to show the graph since your asking how to graph


starting at point (0,1) and with the given slope(-5/4) the easiest way to find the otherpoints is to use this plot system where a/b=slope
(x+b,y+a)
(x+(4),y+(-5))
(0+(4),1+(-5))
(4,-4)
(x+b,y+a) repeat with the previous point
(x+(4),y+(-5))
(4+(4),-4+(-5))
(8,-9)
now you have 3 points to draw a line


OR


if you cant remember how to use the slope to make your points then you will have to find points to make your line.


easiest way to draw the line is to make a chart of x-coordinates that will give u easy y-coordinates to graph. normally i would do {x=0,1} but since we are dealing with a fraction for the slope, i would want to use numbers that would cross cancel and leave whole numbers. I would use {x=4,-4}. i will use these numbers as they are easily divisiable by 4 which is the denominator of the slope. so lets find our y-cordinates:

and
we get these two pairs: and we know the line crosses y-axis at +1.
(4,-4)
(-4,6)
plot the points and draw your line
(-4,6),(0,1),(4,-4)
should look like a "\" line

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