SOLUTION: I have managed to work the rest of this question but the last bits are hell.Please help. I am trying to find the GRADIENT of the line PERPENDICULAR to AB (i) A(3,2)......

Question 26931: I have managed to work the rest of this question but the last bits are hell.Please help.
I am trying to find the GRADIENT of the line PERPENDICULAR to AB
(i)
A(3,2)................B(4,-1)
(ii)
A(-6,3)...............B(6,3)
Answer by venugopalramana(3286) (Show Source): You can put this solution on YOUR website!
gradient of line joining (x1,x2),(y1,y2)is given by (y2-y1)/(x2-x1)
product gradients of 2 perpendicular lines =g1*g2 = -1
so we have gradient of ab =(-1-2)/(4-3)=-3/1=-3=g1
g2=-1/g1=-1/-3=1/3.............the other example also is similar
A(-6,3)...............B(6,3)
g1=(3-3)/(6+6)=0=g1
g2=-1/0= -infinity
RELATED QUESTIONS
In the figure plane E is parallel to plane F, AB is perpendicular to F and AG is the... (answered by MathLover1)

if a graph is created showing ln z against t for this : z= 2e^(4t) - what is the... (answered by Fombitz)

I am sorry to post this again but I have been trying to work this out for almost two... (answered by vleith)

Please help? I am trying to understand this but have no clue what I am doing.... (answered by Alan3354)

HI everyone, Im trying to finish the following problems but I am struggling a bit. I have (answered by nerdybill)

Hi! I am trying to solve this question for my homework, but I am having trouble. The... (answered by Techpriest,MathTherapy)

I managed to do 7,8 :D just now, something clicked :D But, question 9, IMPOSSIBLE :P... (answered by solver91311)

I have two equations, one is a hyperbola and one is a straight line. The line is in the... (answered by KMST)

I am trying to help my daughter with her work but I am not understanding could I please... (answered by bonster)