SOLUTION: I need to know what point lies on the line defined by the equation 4x-3y=9. I tried substituting 0 for X and using -3 as my Y-intercept and my coordinate became (o,3) but apparent

Algebra.Com
Question 267783: I need to know what point lies on the line defined by the equation 4x-3y=9.
I tried substituting 0 for X and using -3 as my Y-intercept and my coordinate became (o,3) but apparently that was wrong. So my only other choices are (3,7), (2,-1/3), or (2,17/3). I cannot figure out how to get any of those solutions. Can you help?

Answer by solver91311(24713)   (Show Source): You can put this solution on YOUR website!




Yes, if you use 0 for then you get -3 for , but that would mean that the point is (0,-3), not (0,3).

So, substitute 3 for :





So not (3,7)

Substitute 2:





Ta da!!

If the third one is correct, then the last one can't be because the last two ordered pairs have the same coordinate and different coordinates. Only one of the last two points could possibly be on the line.


John


RELATED QUESTIONS

Determine the equation of each line. Write the answer in standard form using only... (answered by Alan3354)
I need to verify whether each equation is an identity or not by substituting -1, 0, and 1 (answered by jim_thompson5910)
If the point(3,-2) lies on the circle defined by x^2+y^2+mx-4y-3=0, what is the value of... (answered by stanbon)
I need help on steps for solving a system of equations in substituting, elimination,and... (answered by jim_thompson5910)
Graph each Equation: solve for y. need to find 3 points on a line that intercept. {{{... (answered by stanbon)
I am trying to graph 3y= -5x, I tried by substituting x for 0 then y for 0. I ended up... (answered by josgarithmetic,MathTherapy,greenestamps)
Hi! I have been trying to use old, retired ACT exams to prepare to take the actual... (answered by josgarithmetic,MathLover1,MathTherapy)
Solve for x: {{{sqrt(x+7) + sqrt(x+2) = sqrt(x-1) - sqrt(x-2)}}} When I solve the... (answered by psbhowmick)
I have been stuck on this problem for a while: (12x^-3y^9)/(-3x^-7y^-3) This is what I... (answered by mananth)